题目要求：统计各个数字，空白符以及所有其他字符出现的次数。
[CODE]#include <stdio.h>
main()
{
int c, i, nwhite, nother;
int ndigit[10];
nwhite = nother = 0;
for (i = 0; i < 10; ++i)
ndigit[i] = 0;
while ((c = getchar()) != EOF)
if (c >= ’0′ && c <= ’9′)
++ndigit[c - '0'];
else if (c == ” || c == ‘\n’ || c == ‘\t’)
++nwhite;
else
++nother;
printf(“digits = “);
for (i = 0; i < 10; ++i)
printf(” %d”, ndigit[i]);
printf(“, white space = %d, other = %d\n”, nwhite, nother);
}[/CODE]
提示：
[CODE]amro:~/doc/c$ gcc -o 1.6.1.out 1.6.1.c
1.6.1.c:16:25: 错误： 空的字符常量[/CODE]
请问怎么修改呢？谢谢
>> 本文固定链接: http://www.vcgood.com/archives/2116
#include <stdio.h>
main()
{
int c, i, nwhite, nother;
int ndigit[10];
nwhite = nother = 0;
for (i = 0; i < 10; i++)
ndigit[i] = 0;
while ((c = getchar()) != EOF)
{ if (c >= ’0′ && c <= ’9′)
ndigit[c - '0']++;
else if (c == ” || c == ‘\n’ || c == ‘\t’)
nwhite++;
else
nother++;
}
printf(“digits = “);
for (i = 0; i < 10; i++)
printf(” %d”, ndigit[i]);
printf(“, white space = %d, other = %d\n”, nwhite, nother);
}
have a try.